Oracle Certified Professional, MySQL 5.6 Developer (1z0-882日本語版) - 1z0-882日本語무료 덤프문제 풀어보기

A. SELECT
(SELECT SUM (population)
FROM Country
WHERE Code ='USA'
FROM country
WHERE Code= 'CAN'
)

B. (SELECT SUM (population)
FROM Country
WHERE Code ="USA'

C. SELECT SUM (population)
FROM Country
WHERE Code ="USA"
+ (SELECT SUM (population)
FROM Country
WHERE Code =.'CAN'
)

D. SELECT (
SELECT SUM (population)
FROM Country
SELECT SUM (population)
FROM Country
WHERE Code ='CAN'
)

A. Option C

B. Option E

C. Option D

D. Option A

E. Option B

A. Option C

B. Option D

C. Option A

D. Option B

A. Option C

B. Option D

C. Option A

D. Option B

A. SELECT colors1. Name count (colors2.name)
FROM colors1
INNER JOIN colors2
on colors1. Name =colors2. Name
GROUP BY colors1 .name;

B. SELECT colors1 .name.count (colors2.name)
FROM colors1. Colors2
WHERE
Colors1. Name = (SELECT DISTINCT name FROM colors2 WHERE colors1.name=colors2.name)
GROUP BY colorse1.name,

C. SELECT colors1.name, count(colorse2. Name)
FROM colorse1 .name =colors2.name
WHERE colors1. Name =colors2.name
GROUP BY colors1.name,

D. SELECT colors1.name, count (colors2.name)
FROM JOIN colors2
on colors1 .name =colors2.name
GROUP BY colors1.name;
SELECT colors1.name, count (colors2.name)
FROM colors1
RIGHT JOIN colors1
on colors1 .name =colors2.name
GROUP BY colors1.name;

A. Option C

B. Option E

C. Option D

D. Option F

E. Option A

F. Option B

A. Option C

B. Option D

C. Option A

D. Option B

A. SELECT Name FROM country LIMIT 100,50

B. SELECT Name FROM country LIMIT 35

C. SELECT Name FROM country LIMIT @limitcount

D. SELECT Name FROM country LIMIT RAND ()

E. SELECT Name FROM country LIMIT 100-50

A. Option C

B. Option D

C. Option A

D. Option B

A. Option C

B. Option D

C. Option A

D. Option B